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2012GeomechanicsHomework1Solutions

# 2012GeomechanicsHomework1Solutions - GLY4930 Geomechanics...

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GLY4930: Geomechanics Homework 1 Solutions 1. A soil is collected from below the water table in a split-core sampler with an undisturbed volume of 110 cm 3 . The wet soil has a mass of 212 g. When oven- dried, the mass is 162 g. From this information, determine the: (a) water content w = m w m s × 100% = 50 g 162 g × 100% = 30.9% (b) dry unit weight, γ d = m s g V T = 50 g 9.81 m / s 2 ( 29 110 cm 2 = 14.4 kN / m 3 (c) void ratio, and e = V v V s = V w V s for saturated conditions e = V w V s = V w V T - V w = 50 cm 3 60 cm 3 = 0.833 (d) specific gravity of the soil particles. G s = ρ s ρ w = 162 g 50 cm 3 ( 29 50 g 60 cm 3 ( 29 = 2.7 (note either use CGS units, as in the problem definition, or convert to SI units). 2. Standard Ottawa sand (from Ottawa, Illinois!) consists of uniformly sized, well- rounded, and clean quartz grains with a specific gravity of 2.65. With a standard compactive effort, this sand can be compacted to a maximum dry unit weight of 17.3 kN/m 3 . For this sand, calculate: (a) minimum porosity (when it is compacted to maximum density) e = G s γ w γ s - 1 = 2.65 9.81 kN / m 3 ( 29 17.3 kN / m 3 - 1 = 0.5 n = e 1 + e = 0.5 1 + 0.5 = 0.33 or 33%

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2012GeomechanicsHomework1Solutions - GLY4930 Geomechanics...

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