problem03_76

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.76: a) . ) ( ) 2 / 1 ( 2 2 2 2 2 2 2 2 y x y y x x y x y x dt d y x v v a v a v v v v v v v dt d dt dv + + = + + = + = b) Using the numbers from Example 3.1 and 3.2, m/s. 54 . 0 m/s) 3 1 m/s) 0 . 1 ( ) m/s 30 0 m/s 3 1 ) m/s 50 0 m/s)( 0 . 1 ( 2 2 2 2 = + - + - - = . ( . )( . ( . dt dv The acceleration is due to changing both the magnitude and direction of the velocity. If the direction of the velocity is changing, the magnitude of the acceleration is larger than
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Unformatted text preview: the rate of change of speed. c) 2 2 y x y y x x v v v , a v a v + = + = ⋅ a v v v , and so the above form for dt dv is seen to be . / v a v v v ⋅...
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