Elementary Principles 487 - 11.19 (cont'd) When the feed...

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11- 16 When the feed rate of A equals the rate at which A reacts, N A reaches a steady value. N A would never reach the steady value in a real reactor. The reasons are: () ± 1 In our calculation, V = t , V . But in a real reactor, the volume is limited by the reactor volume; (2) The steady value can only be reached at t . In a real reactor, the reaction time is finite. vt ⇒→ ∞ → ∞ →∞ d. lim lim [ exp( )] lim t A t A t A C Ck t kt C kt = −− == 00 1 0 From part c, t N V A →∞⇒ = , N a finite number, V C AA 11.20 a. MC dT dt QW v =− ±± M CC W vp = = (. . ± 300 100 0 0754 1 0 L) kg / L) = kg kJ / mol C)( mol / 0.018 kg) = 4.184 kJ / kg C oo dT dt Q tT = 0 0797 . ± (kJ / s) = 0, = 18 C o b. dT . kJ s 4.29 kW 18 C C 0 s o o 100 240 0 0797 100 18 240 0 0797 4 287 z z =⇒ = × . . Qdt Q c. Stove output is much greater. Only a small fraction of energy goes to heat the water. Some energy heats the kettle.
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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