Elementary Principles 480 - 11.10 (cont'd) c. 0.45 m = 50...

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11- 9 dx dt , x decreases when t increases dx dt becomes less negative until x reaches 0; Each curve is concave up and approaches x = 0 as t ; increases dx dt becomes more negative x decreases faster. =− < →∞ ⇒⇒ ± ± m x m 200 0 d. dx x m M dt xt 045 0 . ± z z ln . ± .e x p ± xm tx mt 0 45 200 200 ⇒ = F H G I K J Check the solution : () . ± exp( ± ) ± 1 200 200 200 t = 0, x = 0.45 satisfies the initial condition; (2) dx dt satisfies the mass balance. × mm t m x e. ± ln . mt x f =⇒ = 100 2 kg min di 90% ⇒= =
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