Elementary Principles 473 - 11.3 a. mw = a + bt t = 0, mw =...

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11- 2 11.3 a. ± ma b t w =+ tm w == 07 5 0 , ± bg & m t ww = = = + 5 1000 750 50 , ±± b g b g kg h h Balance on methanol: Accumulation = Input – Output M dM dt mm t dM dt t tM fw = =−= + E =− kg CH OH in tank kg h kg h kg h kg 3 , 1200 750 50 450 50 5 0 b. dM t dt Mt 750 0 450 50 z z E −= E t t 750 450 25 750 450 25 2 2 Check the solution in two ways : () , 1 0 750 450 50 t ==⇒ kg satisfies the initial condition; (2) dM dt reproduces the mass balance. c. dM dt =⇒= = ⇒ = + = 0 450 50 9 750 450 9 25 9 2775 2 h kg (maximum) M t t + 0 750 450 25 2 t = −± + 450 450 4 25 750 22 5 2 bg b g t = –1.54 h, 19.54 h d. 3.40 m 10 liter kg 1 m 1 liter kg 33 3 0792 2693 . = (capacity of tank) M t t + 2693 750 450 25 2 t = +
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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