Elementary Principles 472 - CHAPTER ELEVEN 11.1 a. The...

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11- 1 CHAPTER ELEVEN 11.1 a. The peroxide mass fraction in the effluent liquid equals that in the tank contents, which is: x M M p p = Therefore, the leakage rate of hydrogen peroxide is ± / mM M p 1 b. Balance on mass: Accumulation = input – output E =− == dM dt mm tM M ±± , 01 0 0 (mass in tank when leakage begins) Balance on H O 22 : Accumulation = input – output – consumption E F H G I K J dM dt mx m M M kM M p p p p pp , 00 1 0 11.2 a. Balance on H 3 PO 4 : Accumulation = input Density of H 3 PO 4 : ρ = 1834 . g / m l . Molecular weight of H 3 PO 4 : M = 98 00 g /m o l . Accumulation =
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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