Elementary Principles 448

# Elementary - 9.70(cont'd Air fed(25 excess = 1.25(4.76 kmol air kmol O2 kmol air(338 = 2011 kmol O2 d d 2011 kmol 29 kg 1 tonne E = 58.3 tonnes

This preview shows page 1. Sign up to view the full content.

9- 96 b. c. d. Air fed (25% excess) = 1.25(4.76 kmol air kmol O d d 2011 kmol 29 kg 1 tonne dk m o l 1 0 k g E = 58.3 tonnes / d air to boiler) 2 2 3 )( ) ± ( 338 2011 = ⇒⇒ Energy balance on boiler air preheater : 3 o 6 0 2011 kmol 10 mol 2.93 kJ kJ ˆ Table B.8 (125 C) 2.93 5.89 10 kJ/d d 1 kmol mol mol air HQ ⇒= = = × ± Supplementary fuel for incinerator : ± . n 6 97 5 == 11.2 tonne sludge 195 SCM 1 kmol d tonne 22.4 SCM kmol d MW MW MW gas = + =+= 090 010 090 16 010 30 174 ..( . ) ( ) ( . ) ( ) . CH C H 42 6 kg kmol M gas =⇒ (. ) ) ± 975 17 4 G = 1.7 tonne / d (natural gas) CH O CO + 2H O, C H O CO + 3H O 22 2 6 2 +→ + 2 7 2 2 Air feed to incinerator: 3 43 , 11200 kg sludge 0.75 kg sol 19000 kJ 2.5 m (STP) air 1 kmol (air) : 1781 d kg sludge 1 kg sol 10 kJ 22.4 m (STP) d th sludge = , kmol CH 2 kmol O kmol 4.76 kmol air kmol air (air) : 97.5 0.90 (0.10)(3.5) 998 d kmol kmol CH 1 kmol O d th gas ⎡⎤ ×+ = ⎜⎟ ⎢⎥ ⎣⎦ 7 3 kmol air 100% excess air: 2(1781 998) 5558 kmol air/d d 5558 kmol air 29.0 kg air 1 tonne 161 tonne air/d (incinerator air)
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

Ask a homework question - tutors are online