Elementary Principles 413 - 9.51 (cont'd) 1 mol / s fuel...

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9- 61 b. 1 mol / s fuel gas 0.85 mol CH / s 0.15 mol C H / s 42 6 , Theoretical oxygen 2 mol O 0.85 mol CH 1 mol CH s 3.5 mol O 0.15 mol C H 1 mol C H s mol O / s 24 4 22 6 26 2 =+ = 2 225 . Assume 10% excess O O fed = 1.1 2.225 = 2.448 mol O / s 2 × C balance : mol CO / s 2 ± .. ± . nn 085 1 015 2 115 =+⇒ = bg b g b g H balance mol H O / s 2 : ± ± . 2 085 4 015 6 215 33 = b g b g 10% 01 2 225 0 223 4 excess O mol O / s mol O / s 2 ⇒= = ± . n b g Extents of reaction : ± ± . ± ± . ξξ 12 085 015 == = = CH C H 6 mol/s, mol/s Reference states: CH g , C H g , N g , O g , H O l , CO (g) at 25 C 6222 2 o (We will use the values of Δ ² H c o given in Table B.1, which are based on HOl 2 as a combustion product, and so must choose the liquid as a reference state for water) Substance mol kJ mol mol kJ mol CH CH O CO HOv in in out out 4 2 2 ± ² ± ² . . . . n H n H H 0 0 2 225 0 0223 0 115 0 2 1 −− ²² . HH 1 25 44 01 v o C kJ / mol ej Energy Balance : ± ± ² ± ² ± ² ± ² Qn Hn H n H n H ii = ++ CH c o CH c o out in 4 4 ΔΔ mol / s CH kJ mol mol / s C H kJ mol mol / s H O kJ / mol kW kW (transferred from reactor) 6 2 =− + +=
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