Elementary Principles 410

# Elementary Principles 410 - 9.47 Basis : 50,000 mol flue...

This preview shows page 1. Sign up to view the full content.

9- 58 9.47 Basis : 50,000 mol flue gas/h 0.100 (NH ) SO 2 50°C 50,000 mol/h 0.00300 SO 2 0.997 N n 1 (mol solution/h) 42 3 0.900 H O( ) 2 l 25°C n 4 (mol SO /h) 2 n 5 (mol N /h) 2 35°C 1.5 n 2 n 2 (mol NH HSO /h) 43 (mol (NH ) SO /h) 2 n 3 (mol H O( )/h) 2 35°C l 90% SO removal mol h mol SO h 2 2 : ± .. , . n 4 0100 0 00300 50 000 15 0 = = af bg N balance: 2 ± ., , n 5 0 997 50 000 49 850 = = a f mol h mol N h 2 NH balance: S balance: mol NH HSO h 4 + 2 0100 15 2 20 0100 000300 50 000 150 15 5400 270 12 21 2 2 1 2 b g b g b g b g . ±± . ± . ± . ± . ± ± ± nn n n n n n n =+ ⇒= += + + U V | W | = = H O balance 270 mol NH HSO produced 1 mol H O consumed h 2 mol NH HSO produced mol H O l h 2 2 2 : ± . n 3 0900 5400 4725 =− = Heat of reaction: ΔΔ Δ Δ Δ ²² ² ² ² . () HH H H H r o f o NH HSO aq f o NH SO aq f o SO g f o HO ( l ) 44 2 3 kJ mol kJ mol = − −− 2 2 760 890 296 90 28584 47 3 2 ej b g b g b g References : N g SO g NH SO aq NH HSO aq H O l 24 2 34 2 23 b g b g b g b g ,, , , at 25 ° C SO g C 2 50 ,: D ² . HC d T p == z di SO 2 kJ mol 25 50 101 ( C p from Table B.2) SO g C 2 35 D ² . d T p z SO 2 kJ mol 25 35 040 Ng C 2 50
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

Ask a homework question - tutors are online