Elementary Principles 409

# Elementary Principles 409 - 9.46 a. H 2SO 4 aq + 2NaOH aq...

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9- 57 9.46 a. b. H SO aq 2NaOH aq Na SO aq 2H O l 24 2 2 bg b g +→ + 4 H SO solution: : 75 4 11 0 030 ml of 4M H SO solution mol H SO 1 L 75 mL L acid soln mL mol H SO 3 ⇒= . 75 123 9225 9808 2942 29 42 1 349 1163 mL g mL g, (0.3 mol H SO ) g mol g H SO 92.25 g H O 62.83 g H O mol 18.02 g mol H O mol H O 0.30 mol H SO mol H O / mol H SO 22 2 4 2 2 4 b g b g b g .. . . == ⇒− = = r ΔΔ Δ ±± ± . ., . HH H f o soln f o HSO l f o HSO aq r Table B.1, Table B.11 kJ mol kJ mol H SO ej b g =+ = =− = B 44 11 63 81132 67 42 878 74 NaOH solution required: 0.30 mol H SO 2 mol NaOH 1 L NaOH(aq) 10 mL 1 mol H SO 12 mol NaOH 1 L mL NaOH aq 3 = 50 00 . 50 00 137 685 . mL g mL g b g = 12 0 060 2400 24 00 1 2 47 247 06 4 40 mol NaOH 1 L 50 mL L NaOH(aq) mL mol NaOH g NaOH 68.5 g H O 44.5 g H O mol 18.02 g mol H O mol H O mol NaOH .12 mol H O mol NaOH 3 g/mol NaOH 2 2 2 = = = b g r ± . ., . H f o soln f o NaOH s s o NaOH s aq r kJ mol kJ mol NaOH b g = = 412 426 6 3510 46170 Na SO aq : Δ ± . H f o soln f o Na SO s f o Na SO aq kJ mol kJ mol Na SO b g = = 1384 5 117 13857 m total = total mass of reactants or products = (92.25g H SO soln +68.5g NaOH) = 160.75g = 0.161 kg Extent of reaction
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