Elementary Principles 407 - 9.43 a. CaCl 2 s + 10H 2 O l...

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9- 55 9.43 a. b. CaCl s O l CaCl aq r kJ mol 22 2 r o bg b g +→ = = 10H 10 1 64 85 1 , ± . Δ H CaCl H O s H O l CaCl aq r kJ mol 2 2 r o ⋅+→ = = + 64 1 0 2 3 2 4 1 2 b g b g , ± . Δ H 12 6 6 bg b g −⇒ + CaCl s H O l CaCl H O s 2 2 (3) ⇒= = ΔΔ Δ ±± ± . HH H r o r o r o Hess's law kJ mol 31 2 97 26 From (1), Δ ± , H r o f o CaCl aq r f o CaCl s 1 10 =− = ej b g = = Δ ± .. . , H f o CaCl aq r 2 kJ mol kJ mol 10 6485 794 96 85981 9.44 a. b. c. Basis: 1 mol NH SO produced 44 2 2 mol NH 3 (g) 75 ° C 1 mol (NH 4 ) 2 SO 4 (aq) 1mol H 2 SO 4 (aq) 25 ° C 25 ° C 2NH g H SO aq NH SO aq 32 4 4 2 4 b g References : Elements at 25 ° C NH g C 3 ,: 75 ° . ( C d T p =+ = −+ F H G I K J z Δ f o kJ / mol kJ mol Table B.1, B.2) 25 75 4619 183 44 36 HSO a q C 24 25 ° . == Δ f o HSO aq kJ mol H SO 907 51 (Ta.ble B.1) NH SO aq C 4 2 4 b g 25 ° . Δ f o NH SO aq 4 2 4 4 2 4 kJ mol NH SO bg b g 11731 (Table B.1) Energy balance: QH n H n H ii = ∑∑ Δ . out in 4 2 4 kJ kJ 177 kJ withdrawn mol NH SO produced 1 11731 2 44 36 1 907 51 177 b g b g b g bg b g 11 3 2 1914 177 1914 1 4184 25 471 mole % (NH ) SO solution 1 mol (NH ) SO 132 g mol g (NH ) SO
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