Elementary Principles 406

# Elementary Principles 406 - 9.41(cont'd Volume ratio =...

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9- 54 b. Volume ratio cm NaOH(aq) 20.49 cm H SO aq) cm caustic solution / cm acid solution 3 3 24 33 == 6667 325 . ( . HSO a q bg : r m o l H O / 1 m o l H S O 22 4 = 9 ΔΔ Δ ±± ± .. ., HH H f o soln f o HSO l f o HSO aq r kJ mol kJ mol H SO ejej ej b g =+ = = = 44 9 81132 6523 877 NaOH(aq) : The solution fed contains 66 67 113 7534 . cm g cm g e j = , and (0.2 mol NaOH) g mol g NaOH 75.34 g H O 67.39 g H O mol 18.02 g mol H O mol H O 0.20 mol NaOH mol H O / mol NaOH 2 40 00 8 00 800 1 374 187 b g b g = ⇒− = ⇒= = r Δ ± . ., . H f o soln f o NaOH s s o NaOH s aq r kJ mol kJ mol NaOH b g = = = 18 7 426 6 42 8 469 4 Na SO aq Δ ± . H f o soln f o Na SO s f o Na SO aq kJ mol kJ mol Na SO b g = = 1384 5 117 13857 Extent of reaction mol (1) mol HSO f in a l f ed 4 2 4 :( ) ( ) . . nn 4 00 1 0 0 1 0 = + = −⇒ = ν ξ Energy Balance = (0.10 mol) 1385.7 + 2( kJ mol kJ r o f o Na SO aq) f o HOl ) f o HSO aq ) f o NaOH aq) 2 : ± ( ± )( ± ± ± ) .)( ) ( . ) . (( ( ( QH H H H H H = + −− = Δ Δ Δ Δ ξξ 28584 87655 2 469 4 14 2 9.42 a. b. NaCl(aq): Δ ± . H f o f o NaCl s s o Table B.1 given , kJ / mol kJ mol = += B 4110 4 87 4061 NaOH(aq): Δ ± . H f o f o NaOH s s o Table B.1
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## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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