Elementary Principles 398

# Elementary Principles 398 - 9.35 Basis 1 mol C 2 H 6 fed to...

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9- 46 9.35 a. b. Basis : 1 mol C H fed to reactor 26 1273 K, P atm (mol H ) 1 mol C H 2 2 (mols) @ n n H 2 6 T (K), P atm (mol C H ) 2 n C H 6 (mol C H 2 n H 24 4 CH H 2 ⇔+ , K xx x PT K p == × H 2 728 10 17000 6 .e x p [ , / ( ) ] (1) Fractional conversion = f mols C H react mol fed bg ξ (mol) mol C H mol C H mol H mols mol C H mol mol C H mol mol H mol 2 6 2 4 H2 H 2 2 2 = =− = = =+ U V | | | W | | | = + = + = + f nf x f f x f f x f f 1 1 1 1 1 1 b g K x K f ff f f pp f f f f =⇒ = = −+ = + + H 2 P P P P 2 2 1 1 1 22 2 11 1 12 −= = + F H G I K J fK f f K K p p p ej P P References : C H g C H g H g at 1273 K 2 ,, Energy balance: ΔΔ H H nH ri i i i + 0 1273 K out in ±± ± ± H i in inlet temperature reference temperature 0 ± HC d T ip i T out = z 1273 energy balance f H f C dT f C dT f C dT rp T p T p T 1273 K kJ H 2 Δ ± b g di +− + + = zzz 10 1273 1273 1273 rearrange, reverse limits and change signs of integrals
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## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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