Elementary Principles 392 - 9-31 (cont'd) ^ ^ ^ ^ ^ ^ H = H...

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9- 40 d. e. o r34512 o ˆˆ ˆ Substitute for , , and through r1 6 52 83 1 24 out out out out ˆˆˆˆˆˆ (1.00) (4.00) (6.00) (4.00) (6.00) (0.3479 4.28 10 0.9285 10 4.697 10 ) HH H H H H H H HT T T T ξ Δ −− ⇒Δ = Δ + + + Δ= + × + × × ± ± ± ± o out 972.24 kJ/mol = 0 E-Z Solve 2223 C T ⇒= If only the first term from Table B.2 is used, kJ / mol, kJ / mol, , , out out out ² () ( ) ² .( ) . ² . ² ) ² ) ² ) HC d T C T H T H T ip i p i T == =− = = = = z 25 003515 200 25 615 531 00291 25 0 0295 25 003346 25 25 12 3 45 o o ˆ Substitute for (=1 mol/s), ( 904.7 kJ/mol) and through 6 o out out E.B. (1.00) (4.00) (6.00) (4.00) (6.00) 0 2788 0=0.3479 969.86 2788 C % error= H H H H H H TT Δ=Δ + + + = −⇒ = ± ± ± oo o C 2223 C 100 25% 2223 C ×= If the higher temperature were used as the basis, the reactor design would be safer (but more expensive). 9.32 a. Basis : 100 lb m coke fed ⇒⇒ 84 lb C 7.00 lb - moles C fed 7.00 lb - moles CO fed m2 400°F 7.00 lb-moles CO 2 (lb-moles CO) n 1 77°F 7.00 lb-moles(84 lb
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