9- 36d. substancekmol / hkJ / kmolkmol / hkJ / kmolCH OH75.43ONHOHCHOHininoutout3222±²±².....nHnHnnnns−−−19522022 63163200218836201841082 29351082 291739023774022092052 8088800168102265Energy Balance :ΔHnHii=−=∑∑²²outin0 ⇒+−+=−×18410168102209202377047 406 102566nns.(4) We now have four equations in four unknowns. Solve using E-Z Solve. ±ns==58.8 kmol H O v18.02 kgh1 kmolkg steam fed h2bg1060±.n2226=kmol Oh2, ±.n51358=kmol Hh2, ±.n698 00=kmol H O h2Summarizing, the product gas component flow rates are 22.63 kmol CH3OH/h, 2.26 kmol O2/h, 82.29 kmol N2/h, 52.80 kmol HCHO/h, 13.58 kmol H2/h, and 98.02 kmol H2O/h ⇒272 kmol h product gas8% CH OH, 0.8% O30% N19% HCHO, 5% H37% H O32222,,,Energy balance on waste heat boiler.Since we have already calculated specific enthalpies of all components of the product gas at the boiler inlet (at 600
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.