Elementary Principles 387

# Elementary Principles 387 - 9.29(cont'd ym P = pm Tm 0.42...

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9- 35 c. yP p T p T mm m m m =⇒ = ∗∗ bg b g b g bg 042 760 3192 .. mmHg mmHg = Antoine equation mmHg 44.1 C ⎯→ ⎯⎯⎯⎯ ⎯= = pT 319 2 . D Moles HCHO formed : = × = 36 10 3003 5280 6 kg solution 0.37 kg HCHO 1 kmol 1 day 350 days 1 kg solution kg HCHO 24 h kmol HCHO h . . but if all the HCHO is recovered, then this equals ± n 4 , or ± . n 4 = kmol HCHO h 70% conversion : 52.80 kmol HCHO 1 kmol CH OH react 1 kmol CH OH fed kmol feed gas h 1 kmol HCHO formed 0.70 kmol CH OH react 0.42 kmol CH OH 33 1 = ± n f ⇒= ± . n f 17959 kmol h Methanol unreacted: ± . . n 1 0 42 179 59 1 0 70 22 63 = = b g b g kmol CH OH fed kmol CH OH fed h 1 kmol CH OH fed kmol CH OH h 3 3 N balance: kmol h kmol N h 2 2 ± . . n 3 179 6 058 0 79 82 29 == b g b g Four reactor stream variables remain unknown — ± , ± , ± nnn s 25 , and ± n 6 — and four relations are available — H and O balances, the given H 2 content of the product gas (5%), and the energy
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## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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