Elementary Principles 384 - 9.27 (cont'd) Energy balance: H...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
9- 32 Energy balance: Δ Hn H H n C T T ii i i p i i =⇒ = = 00 ±± , out , in out in ej bg (Assume adiabatic) 10 lb - moles C H 120 lb 0.40 Btu h1 l b - m o l e 1 b F FF F 91 2 m m C 3 H 6 C 4 H 10 C 6 H 6 in effluent C 6 H 6 fed to reactor L N M O Q P −+ +− = = ° B B A A D DD D D 200 400 2 50 42 08 057 200 400 417 5812 055 200 400 30 0 7811 0 45 200 400 40 0 7811 0 45 77 0 323 b g e b g b g b g .. . . . . . . TT (Refer to flow chart of Part b: T = ° 323 F ) References : CH l, CH l, CH l, CH l a t 77 F 36 41 0 66 2 ° ± HC M T ip i i Btu lb - mole Btu lb F lb lb - mole F mm b g b g b g =⋅ ° ° 77 Substance (lb - mole / h) (Btu / lb - mole) (lb- mole / h) (Btu / lb - mole) CH 12 .0 in in out out 4 2 ² ± ² ± . . n H n H 0 2 50 7750 417 0 10330 40 0 8650 30 0 11350 10 0 15530 10 −− Energy balance on reactor : QH nH v == + ∑∑ Δ Δ ² ± ² ± ² ± r o out in 2 2 = + +++ −= 10 0 39520 1 2 50 7750 417 10330 30 0 11350 10 0 15530 40 0 8650 183000 . . . . b g b g b g b g b g b g b g Btu h heat removal 9.28 a. Basis
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online