Elementary Principles 343

# Elementary Principles 343 - 8.89 (cont'd) R |H | | Table...

This preview shows page 1. Sign up to view the full content.

8-64 8.89 (cont’d) Table B.6 F = 85.6 C) = (2652 kJ / kg) 0.4303 Btu lb kJ kg Btu / lb F = 65.4 C) = (274 kJ / kg) 0.4303 Btu / lb oo m m m F H G G I K J J = = R S | | | T | | | ± ( ± ( () H H HOv HOl 2 2 186 1141 149 118 bg ² ² ± (. , . QmH == L N M O Q P =− ⇒× Δ 46 3 47 360 474 10 4 lb min ) (118 1141) Btu lb Btu / min Btu minavailable at 149 F m m o d. Refs: HPO , HO F 34 2 ll @77 ° substance in lb H PO in Btu lb in in out out m m 2 mH m H m H v ±± .. ± . 28% 100 1395 42% 0 667 3413 03333 1099 −− ± . H HPO, 2 8% Btu 1 lb - mole H PO 0.3867 lb H PO lb - mole H PO 98.00 lb H PO 1.00 lb soln 0.705 Btu F lb F Btu lb soln 33 m m m m m = + −° ⋅° = 5040 125 77 1395 ± . . H 4 2% Btu 1 lb - mole H PO 0.5800 lb H PO lb - mole H PO 1.00 lb sol. 0.705 Btu F lb F Btu lb soln m m m m m = + ⋅° = 5040 1867 77 . ± ,. HH H l H O psia, 186 F 77 F kJ kg Btu lb 2 m bgb g b g b g ° = 37 2652 104 7 1096
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online