Elementary Principles 342 - 8.89 P2 O5 + 3H 2 O 2H 3 PO 4...

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8-63 8.89 PO 3HO 2HPO 25 2 3 4 +→ a. wt% P O wt% H PO mol H 3 PO 4 g H 3 PO 4 mol g total = × B B A n m n m tc 14196 100% 29 8 0 0 100% . , . bg b g P where nm t = = mol P O and total mass . wt% H PO wt% P O wt% P O 34 2 5 2 5 == 29800 14196 1381 . . . b. Basis: 1 lb m feed solution 28 wt% PO w t% HPO 38 67 . (lb H O( )), 1 lb solution, 125°F m m 12 v 0.3867 lb H PO m3 4 0.6133 lb H O m2 m T , 3.7 psia (lb solution), m 2 m T 0.5800 lb H PO /lb 4 0.4200 lb H O/lb m m H PO balance 0.3867 :. . =⇒ 05800 0 667 22 mm lb m solution Total balance: 1 0 3333 1 =+⇒= mm m r . l b H O Evaporation ratio: 0.3333 lb H O v lb feed solution m c. Condensate: P T l = ⇒= = = 37 654 000102 353145 2205 00163 . . .. / ./ . psia 0.255 bar
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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