Elementary Principles 330

# Elementary Principles 330 - 8.70 Vroom = 141 ft 3 DA = dry...

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8-51 8.70 V m h room 3 DA 3o 3 m o m a m2 m m ft . DA = dry air. = ft lb - mol R 0.7302 ft atm lb DA lb - mol atm 550 R lb H O lb H O / lb DA = = == 141 140 29 1 101 0205 0 0203 . . . . From the psychrometric chart, F, h T F V ft / lb DA T H Btu / lb db o a rw b o3 m dew point o m Th === 90 00903 67% 805 14 3 77 3 44 0 011 439 . . ± . . ± .. . 8.71 T T h r db ab C C He wins ⇒= 35 27 55% 8.72 a. TT hh T ra wb db dew point Fig. 8.4-1 2 C, C kg H O kg dry air C 40 20 33%, 0 0148 255 . . b. Mass of dry air: m da × 2.00 L 1 m 1 kg dry air 10 L 0.92 m kg dry air 3 33 22 10 3 . from Fig. 8.4-1 Mass of water: 2.2 10 kg dry air 0.0148 kg H O 10 g 1 kg dry air 1 kg g H O 2 3 2 × = 3 0033 c. ± . H 40 78 0 0 65 77 4 °≈ = C, 33% relative humidity kJ kg dry air kJ kg dry air bg b g ± . H 20 57 5 C, saturated
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## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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