Elementary Principles 319 - 8.63 (Cont'd) S balance on...

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8- 40 8.63 (Cont’d) S balance on mixing point: 012 27273 0 45 172730 2 000 10 100% 405% 5 22 .. . . bg b g b g += × = XX S (b) Draw system boundary for every balance to enclose freezer and mixing point (Inputs: fresh feed and recycle streams; output; slurry leaving freezer) Refs : S, H O 2 l at −° 7C substance 12% soln kg h 45% soln kJ kg HOs in in out out 2 ± ² ± ² ± ² mHm H m H 27273 108 172730 28 180000 0 20000 337 −− Solutions : ² . HT T b g =− 4 00 7 kJ kg Ice : ²² ² . HH T H mm − ° ≈− ° ⇒− D ΔΔ CC kJ mol kJ kg Table B.1 b g 0 6 0095 337 E.B. ±± ± ² ± ² . QHm H m H ci i i i == = −× ∑∑ Δ out in kJ 1 h 1 kW h 3600 s 1 kJ s kW 1452 10 4030 7 8.64 a. B=n-butane, I=iso-butane, hf=heating fluid. ( ) . C ph f =⋅ 262 kJ/ kg C o di 24.5 kmol/h @ 10 o C, P (bar) 24.5 kmol/h @ 180 o C 0.35 kmol B(l)/h 0.35 kmol B(l)/h ± ( Q kW) ± m (kg HF / h), T( C)
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