Elementary Principles 318

# Elementary Principles 318 - 8.62 (cont'd) H = - H m 0 C + C...

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8- 39 8.62 (cont’d) ΔΔ ±± . HH C d T mp =− ° + = + −° ⋅° A z 0 217 390 0 26 C 6.01 kJ 1 mol 10 g mol 18.02 g 1 kg kJ 26 C kg C kJ kg 3 Table B.1 bg HO C 2 l ,: 50 ° C C 22 ll ,, 05 0 °→ ° b g Δ ± HC d T p == ° = z A 0 50 0 209 0.0754 kJ 50 C 1 mol 1000 g mol C 18.02 g 1 kg kJ kg Table B.2 HO , C HO, C 1 0 0C C C 222 2 2 vll v v 60 0 100 60 °° ° ° ° b gb gbg : Δ Δ ± . . ± H C dT H v p = ⋅° ++ A A A z 0 0754 kJ 100 0 40 656 2599 100 60 di C mol C kJ mol 46.830 kJ 1 mol 1000 g mol 18.02 g 1 kg kJ kg Table B.2 Table B.1 Table B.2 2 ( v ) Energy balance: Q H mH ii = × = ∑∑ Δ out in 5 1.06 10 kJ 1 min 1 kW min s 1 kJ s 60 1760 kW 8.63 Basis: 20,000 kg/h ice crystallized. S = solids in juice. W = water 0.88 H O( )(W) (kg/h) juice m 1 l 2 0.12 solids(S) 20°C (kg/h) m 2 preconcentrate (kg S/kg) x 2 (kg W/kg) x 2 (1 – ) freezer Q f Slurry(10% ice), –7°C 20,000 kg W( )/h s kg residue/h m 4 0.45 kg S/kg 0.55 kg W( )/kg l filter (kg/h) product m 5 0.45 kg S/kg 0.55 kg W/kg 20,000 kg W( )/h s (kg/h), 0.45 S, 0.55 W m 4 separator
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