Elementary Principles 290

# Elementary Principles 290 - 8.29 a 75 liters C 2 H 5 OH l...

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8- 11 8.29 a. 75 liters C H OH 789 g 1 mol liter 46.07 g mol C H OH 25 23 l l bg = 1284 () . . CT p CH OH o 3 kJ / (mol C) =+ × 01031 0557 10 3 ej (fitting the two values in Table B.2) 55 L H O 1000 g 1 mol liter 18.01 g mol H O 2 2 l l = 3054 . C p HO 2 kJ mol C =⋅ ° 00754 1284 mol C 2 H 5 OH(l) (70.0 o C) 3054 mol H 2 O(l) (20.0 o 1284 mol C 2 H 5 OH (l) (T o C) 3054 mol H 2 O(l) (T o C) 3 70 25 o Integrate, solve quadratic equation 0 1284 0.1031 0.557 10 3054 0.0754 liquids 0ad i ab a t i c T=44.3 C TT Td T d T QUH Q × + =Δ ≅Δ ⇒⇓ = ∫∫ b. 1. Heat of mixing could affect the final temperature. 2. Heat loss to the outside (not adiabatic) 3. Heat absorbed by the flask wall & thermometer 4. Evaporation of the liquids will affect the final temperature. 5. Heat capacity of ethanol may not be linear; heat capacity of water may not be
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## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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