Elementary Principles 280 - CHAPTER EIGHT 8.1 a. U (T ) =...

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8- 1 CHAPTER EIGHT 8.1 a . ± () . . UT T T =+ 2596 0 02134 2 J/mol ± ± ± UU T ref 0 0 100 2809 0 oo o o C J/mol C C (since U(0 C)=0) == = b. We can never know the true internal energy. ± U 100 o C is just the change from ± U 0 o C to ± U 100 o C . c. QW U E E kp −= + + ΔΔ Δ EE W = 00 0 ,, QU = Δ (. ) [ ( ) 30 2809 0 8428 8400 mol J / mol] J J d. C U T dU dT T v V = F H G I K J + ±± [. . ] ± 2596 0 04268 J / (mol C) o Δ ± ( . . ) . . ± ( [ . ( ) . ( ) ] UC T d T T d T T T v T T + = + O Q P P F H G G I K J J =⋅ + = zz 1 2 2596 0 04268 0 04268 2 2596 100 0 0 02134 100 0 8428 8400 0 100 2 0 100 2 mol) J / mol) mol) (J / mol) J J 8.2 a. CCRC T vp v =− ⇒= + °− ° 353 0 0291 8 314 .. [ . bg b g b g J / (mol C)] [J / (mol K)] 1 K 1 C + ⋅° CT v 27 0 0 0291 [ J/(mol C)] b. ] 100 100 2 100 25 25 25 ˆ 35.3 0.0291 2784 J mol 2 p T HC d T T Δ= = + = c. Δ . U C dT C dT RdT H R T ==− = = = z z z 25 100 25 100 25 100 2784 8 314 100 25 2160 b g Jmo l d. ± H is a state property 8.3 a. T v [] . . . kJ / (mol C) o ⋅= + × × −− 0 0252 1547 10 3012 10 59 2 atm L atm L / (mol K)
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