Elementary Principles 277 - 7.54 (a). Point 1 - surface of...

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7-32 7.54 (a) . Point 1- surface of fluid . P 1 31 = . bar , z 1 7 = + m , u 1 0 = ms bg Point 2 - discharge pipe outlet . P 2 1 1 = = atm bar .013 , z 2 0 = m , u 2 = ? Δ ρ = ⋅× =− 1013 31 2635 .. . bar 10 N 1 m m bar 0.792 10 kg 53 23 22 gz Δ= 9.8066 m m s 68.6 m s 2 7 Bernoulli equation m s m s ⇒= = + = Δ Δ Δ u P 2 2 68 6 3321 . Δ uu 2 2 0 2 2 2 23321 6642 258 == = (. ) . . m / s ± ) V π 100 2580 122 2 cm cm 1 L 60 s 4 1 s 10 cm 1 min L/min 2 33 (b) The friction loss term of Eq. (7.7-2), which was dropped to derive the Bernoulli equation, becomes increasingly significant as the valve is closed. 7.55 Point 1- surface of lake . P 1 1 = atm , z 1 0 = , u 1 0 = Point 2 - pipe outlet . P 2 1 = atm , zz 2 = ft u V A 2 2 2 95 05 1049 353 × = ± . gal 1 ft 1 144 in 1 min min 7.4805 gal in 1 ft 60 s ft s 32 2 Pressure drop: Δ PP P 0 12 L Z z Fz z = ° = F H G I K J =⋅ = sin ) 30 2 0 041 2 0 0822 Friction loss: ft lb lb (ft lb lb fm Shaft work: -8 hp
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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