Elementary Principles 243 - 6.100 (cont'd) ln X * = 1406 ln...

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6- 77 6.100 (cont’d) ln . ln . . * * .965 .406 .406 Xp X e pp NO NO NO =− = = 1406 1965 0140 22 2 11 1 K F == 0.140 (kg NO / 100kg gel)(mmHg) 2 1.406 ;. β 1406 b. Mass of silica gel : m g π *(0.05m) (1m) 10 L 0.75kggel 1m L 5.89 kggel 23 3 Maximum NO 2 adsorbed : p m ads NO 1.406 2 2 2 in feed 0.010(760 mmHg) 7.60 mmHg 0.140(7.60) kg NO 5.89 kggel 100 kggel 0.143 kg NO = = Average molecular weight of feed : MW MW MW NO air =+ = + = 001 099 001 4601 099 290 2917 2 .( ) ) ( .) (.)( (. ) . kg kmol Mass feed rate of NO 2 : ± m 8.00 kg 1kmol 0.01kmol NO 46.01kg NO h 29.17 kg kmol kmol NO 0.126 kg NO h 2 2 Breakthrough time : t b = 0.143 kg NO 0.126 kg NO / h 1.13 h 68 min 2 2 c. The first column would start at time 0 and finish at 1.13 h, and would not be available for
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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