Elementary Principles 242 - 6.99 (cont'd) 50% CCl4 adsorbed...

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6- 76 6.99 (cont’d) 50% CCl 4 adsorbed nn c c4 mol CCl = = 0500 0662 0 . (= n ads ) Total moles in tank : n tot ads mol =1.919 mol = = 0 1985 00662 (. . ) Pressure in tank . Assume T = T 0 and V = V 0 . P nR T V == F H G I K J F H G I K J = tot atm 760 mm Hg atm 735 mm Hg 0 0 1919 0 08206 307 50 0 ) ) ( ) . y n n p C c = ⇒= c tot 44 mol CCl mol mol CCl mol mm Hg) = 26.2 mm Hg 1919 00345 0 0345 760 . . . .( c. Moles of air in tank mol air = 1.853 mol air :( . . ) nnn ac = = 00 1985 01324 y n n n n py P T V c c c c c cc tot = + =⇒ = × += L N M O Q P ×⋅ = 1853 0 001 1854 10 1854 0001 1854 10 0 08206 50 0 1 3 0 0 3 . .. . . . mol CCl mol mol CCl mol = mol L atm 307 K 760 mm L mol K atm 0.710 mm Hg 4 4 tot air X p p X c ** . . . ) .) . gCCl gcarbon g CCl adsorbed g carbon 4c 4 F H G I K J = + + = 00762 10 0 9 6 0 0762 0 710
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