Elementary Principles 234 - I 6.86 x a = . b0.5150 gg b1101...

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6- 68 6.86 x a I 0.5150 g g mol 0.5150 g g mol 100.0 g g mol mol solute mol = + = bg b g b g b g b g 1101 9410 0 00438 . .. . Δ Δ Δ Δ Δ Δ T RT H x T T x x xx T T m m m s m m s s ss m m =⇒ = == ° ° = 0 2 0 00438 049 0 00523 ± . . . I II I II II I II I C 0.41 C mol solute mol solution 1 mol solvent 94.10 g solvent 0.4460 g solute 0.00523 mol solute 1 mol solvent 95.60 g solvent g solute mol = 0 00523 8350 . . Δ Δ ± . . H RT T x m m m s 0 2 2 8314 2732 500 0 00523 6380 6 38 J mol kJ / mol 6.87 a. ln * pT H RT B sb v b 0 0 =− + Δ I , ln * H RT B s v bs + Δ II Assume ΔΔ HH vv II I ; TT T s 00 2 ln ln ** PT H RT T H R T b s v bb s vb s b b 0 0 0 2 11 −= −− F H G I K J b. Raoult’s Law : xpT b s 1 b gbg ln 1 0 2 0 2 −≈ ⇒ = HT RT T RT H x b b b v Δ Δ 6.88 90 g ethylbenzene m 1 (g styrene) 100 g EG
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