Elementary Principles 221 - 6.73 (cont'd) Equilibrium...

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6- 55 6.73 (cont’d) Equilibrium condition: At G1, p HS 2 atm atm == 0 04 18 0 072 .. . bg b g ⇒= = = × x p H 3 3 0 072 267 10 2 2 2 atm 27 atm mol fraction mole H S mole . . Strategy: Overall H 2 and HS 2 balances ± , ± nn 12 ± n 2 + air flow rate volumetric flow rate at G4 2 and solvent balances around absorber ± , ± 34 0 998 4 . ± n = solvent flow rate Overall H balance: 2 100 0 96 0 999 961 11 b g ± . =⇒ = mol h Overall H S balance: 2 100 0 04 0 001 390 96.1 2 1 b g ±± ± . ± =+ = = n n mol H S h 2 Volumetric flow rate at stripper outlet ± V G4 200 + 3.90 mol 22.4 liters STP K h 1 mol 273 K Lh r = + = b g b g 273 40 5240 2 and solvent balances around absorber: 100 0 04 0 002 0 001 1335 1952 0 998 1 2 67 10 5830 41 3 3 43 3 b g di ± . ± . ± . . += + = =−× U V | W | ⇒≈= n x Solvent flow rate 0 998 4 . ± n 5820 mol solvent h 6.74 Basis:
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