Elementary Principles 219 - 6.72 a. G = dry natural gas, W...

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6- 53 6.72 a. G = dry natural gas, W = water ± ± n n 3 4 m 6 o (lb - mole G / d) (lb - mole W / d) 10 lb W /10 SCF gas 90 F, 500 psia Absorber ± ( n 7 lb - mole W / d) 40 10 6 1 2 . / ± ( ± [ × × SCF / d 4 80 = 320 lb W d lb - mole G / d) lb - mole W(v) / d] m n n Overall system D.F. analysis 5 unknowns ( feed specifications (total flow rate, flow rate of water) water content of dried gas balances (W, G) 0 D.F. : ± , ± , ± , ± , ± ) nnnnn 12347 2 1 2 Water feed rate : ± . n 2 17 78 == 320 lb W 1 lb - mole d1 8 . 0 l b lb - moles W / d m m Dry gas feed rate : ± . .. n 1 6 4 17 78 1112 10 = × −= × SCF 1 lb - mole d 359 SCF lb - moles W d lb - moles G / d Overall G balance : ±± ± . nn n 13 3 4 1112 10 =⇒= × lb - moles G / d
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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