Elementary Principles 199 - 6.44 (cont'd) b. Basis 1 kg...

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6- 33 6.44 (cont’d) b. Basis 1 kg liquid feed n o (mol), 40 o C, 1.2 atm 0.90 mol SO 3 /mol 0.10 mol G/mol 1 kg 98% H 2 SO 4 0.98 kg SO 3 0.02 kg H 2 O n 1 (mol), 40 o C, 1.2 at m y 1 mol SO 3 /mol (1- y 1 ) mol G/mol m1 (kg) 15% oleum 0.15 kg SO 3 /kg 0.85 kg H 2 SO 4 /kg Equilib riu m @ 40 o C i) y p P 1 3 3 40 115 760 151 10 = ° == × SO 3 C, 84.4% mol SO mol bg . . ii) H balance: kg H SO 2.02 kg H 98.08 kg H SO kg H O 2.02 kg H 18.02 kg H O m H SO 2.02 kg H 98.08 kg H SO kg 2 24 2 2 12 098 002 085 128 4 4 1 .. . . + =⇒ = m But since the feed solution has a mass of 1 kg, SO absorbed kg 0.28 kg SO 10 g 1 mol kg 80.07 g mol 3.5 mol balance: 0.10 mol mol 3 3 3 =− = = ⇒= =− × = = E 128 10 350 1 151 10 389 039 01 0 3 1 0 1 . . . . di nn Gn n n n ±² ³³³³³³³³³³³³³³ ´ V = 3.89 mol 22.4 L STP 313K 1 atm 1 m 1 kg liquid feed mol 273K 1.2 atm 10 L .33 10 m kg liquid feed 3 3 -2 3 8 6.45 a . Raoult’s law can be used for water and Henry’s law for nitrogen.
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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