Elementary Principles 197 - 6.42 (cont'd) N 2 : n4 = 3.76...

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6- 31 6.42 (cont’d) N: 3 m o l+ mol NH 2 mol N 4 mol NH mol N O : 200 mol mol NH 5 mol O 4 mol NH mol NH 3 mol O 4 mol NH mol O HO : m o 6 mol H O 4 mol NH mol H O mol = mol converter effluent 68.7% N 7.0% O 15.5% H O 2 32 3 2 2 3 3 2 2 3 2 total 22 2 n n n n 4 5 6 76 2 00 3 7535 97 3 765 20 36 100 mol NH 170 4 97 765 170 4 1097 88% NO, == =− −= ⇒= ++ + .. . . (. . . ) ., , bg iii) Reaction: NO O H O HNO 2 43 2 4 23 + + HNO bal. in absorber: mol NO react 4 mol HNO 4 mol NO mol HNO 3 3 3 n 8 97 97 H O in product: mol HNO 63.02 g HNO g H O 1 mol H O mol 55 g HNO 18.02 g H O mol H O 2 33 2 2 2 n 9 97 45 277 56 = = . H balance on absorber: mol H mol H O added 2 170 4 2 2 97 277 6 2 1557 7 7 . b g b g b g += + n n Vl 63 3 2 2 mol H O 18.02 g H O 1 cm 1 m 1 mol 1 g 10 cm m HO × 281 10
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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