Elementary Principles 194 - 6.39 (cont'd) Dew point = 46.5...

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6- 28 Dew point C C mm Hg mm Hg mol H O mol 2 = ° = = 465 77 6 780 0 0995 .. . . yP p y ww w bg But 2 0.0995 11.05 mol H O 100 w w n yn n == = + (Rounding off strongly affects the result) C balance: 3 4 100 0 000527 3 0 000527 4 0 0148 0 0712 nn pB += + + + b g b g b g . . 3 4 8 969 1 . ( ) ( )( ) ( )( ) ( )( ) H balance: 8 10 100 0.000527 8 0.000527 10 11.05 2 + + ⎣⎦ ( ) 81 0 2 3 . 0 4 7 2 () ( ) () 38 41 0 0 49% C H 1.25 mol C H Solve 1 & 2 simultaneously: 51% C H 1.30 mol C H Answers may vary 8% due to loss of precision p B n n = ⎧⎫ ⎪⎪ ⇒⇒ ⎨⎬ = ⎩⎭ ± 6.40 a. ± / ± / ±± LL x x GG y y 12 2 2 1 1 1 1 (lb - mole C H h) (lb - mole h) (lb - mole C H / lb - mole) (lb - mole C H / lb - mole) (lb - mole / h) = 1 lb - mole / h (lb - mole C H / lb - mole) 0.07 (lb - mole C H / lb - mole) (lb - mole N / lb - mole) 0.93 (lb - mole N / lb - mole) 10 22 10 22 22 Basis: lb - mole h feed gas ± G 2 1 = N balance: 1 2 b g b g bg bg b g 093 1 1 1 11 . . =− ⇒− = GyGy 98.5% propane absorption ⇒= × ± ± . Gy 3 1 0 985 1 0 07 105 10 2 b g b g b g 1 & 2
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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