Elementary Principles 189 - 6.34 Basis: 500 lb m hr dried...

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6- 23 6.34 Basis: 500 lb hr dried leather m (L) lb - moles / h)@130 F, 1 atm lb - moles dry air / h)@140 F, 1 atm lb - moles H O / lb - mole) (1- lb - moles dry air / lb - mole) lb h) 500 lb h 0.61 lb H O(l) / lb 0.06 lb H O(l) / lb 0.39 lb L / lb 0.94 lb o o 2 m m m2 m m mm ± ( ± (( )( ± (/ / n ny y m 1 0 1 1 0 m L/lb Dry leather balance: lb wet leather hr m 0 39 0 94 500 1205 00 .. =⇒ = bg b g Humidity of outlet air: F mm Hg) 760 mmHg mol H O mol HO 2 2 yP p y 11 050 130 050 115 0 0756 =∗ ° = = . .( . H O balance: 0.61 lb hr lb m hr lb - moles H O 18.02 lb hr 1 lb - mole lb - moles hr 2m b g af 1205 0 06 500 00756 517 5 1 1 =+ E = ( ) . . . n n Dry air balance: lb - moles hr lb - moles hr n 0 1 0 0756 517 5 478 4 =− = . ) . V inlet 3 53 lb - moles 359 ft STP R hr 1 lb - mole 492 R .09 10 ft hr = ° 478 4 140 460
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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