Elementary Principles 185 - 6.31 a. Basis: n0 mol feed gas...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
6- 19 6.31 a. Basis: mol feed gas 0 ± n . S solvent = , G solvent - free gas = Inlet dew point = 0 Ty P p T y pT P oo d o o do o ⇒= = bg ( 1 ) Saturation condition at outlet: yP p T y P ff f f 11 =∗ ⇒ = di (2) Fractional condensation of S = 0 fn n y f = 20 () 1 ⎯→ nn f p T P 0 0 (3) Total mole balance: Eq. 3 for ±± ± ± nnn nf P n do o 012 102 10 0 1 =+⇒=− =− (4) S balance: 0 (1) - (4) ny n y n np T P n P P p do o do o f f do o 01 1 2 0 0 00 =+ L N M M O Q P P F H G G I K J J + ± ± −∗ L N M M O Q P P 1 1 fp T P fp T P P do o do o f f b g b g ∗− L N M M M O Q P P P P fp T do P o f do P o f f ej e j 1 1 y 1 [mol S(v)/mol] (sat’d) (1–y 1 ) (mol G/mol) n 0 (mol) @ T 0 ( ° C), P 0 (mm Hg) y 0 (mol S/mol) (1-y 0 ) (mol G/mol) T d0 ( ° C) (dew point) n 2 (mol S (l)) n 1 (mol) @ T f ( ° C), P 4 (mm Hg) Condensation of ethylbenzene from nitrogen
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online