Elementary Principles 168 - 6.3 (cont'd) ln p (45o C) = - b...

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6- 2 6.3 (cont’d) ln ( . . .. . . pp ∗∗ =− + +⇒ = ×= 45 18 49 2310 234 5 234 5 100% 15% o C) 4151 45 273.2 mm Hg error bg c. p = F H G I K J −+= 118 3 760 29 5 77 45 29 5 118 3 327.7 mm H . . g 327 7 234 5 234 5 100% 39 7% . . error 6.4 Plot p + log . scale vs 1 T 2732 (rect. scale) on semilog paper straight line: slope = 7076 2167 K , intercept . ln . .e x p . . p T p T = + = + + L N M O Q P mm Hg 7076 (C ) 7076 ) oo 2732 2167 2732 2167 Δ H R v = 7076K Δ ± H v = = 7076 K 8.314 J 1 kJ mol K 10 J 58.8 kJ mol 3 6.5 ln p* = A/T(K) + B T( o C) p*(mm Hg) 1/T(K) ln(p*) p*(fitted) T( o C) p*(fitted) 79.7 5 0.002834 1.609
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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