Elementary Principles 165 - 5.81 (cont'd) Final: Tc ' = c ....

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5- 53 5.81 (cont’d) Final T R + R = 830 R T P + = 44.8 atm c oo o T=550 F r c o :' . . . . . .' . ' . . . . = F H G I K J F H G I K J ⎯→ ⎯⎯ ⎯= = F H G I K J F H G I K J 0104 0131 986 4 0027 22716 122 47.7 atm 33.5 atm ± ± ' ' .. . . . V= VP RT = 2.2 ft 0.131 lb - mole 44.8 atm 830 R lb - mole R 0.7302 ft atm =1.24 z = 0.85 P= znRT V lb - mole ft atm lb - mole R R 2.2 ft atm r ideal c c 3 o o 3 Fig. 5.4-2 3 o o 3 di = = 085 0131 7302 1009 7 37 3 5.82 a. Volume of sample: g 1 cm g cm 33 342 159 215 . = O i n C h a r g e : 2 n 1.000 L 2.15 cm 10 L km 499.9 kPa 1 atm 0.08206 La tm mol K K 101.3 kPa 0.200 mol O O 3 2 2 = = 300 Product n 1.000 L 1950 kPa 1 atm 0.08206 mol K 756.6 K 101.3 kPa 0.310 mol product p = = Balances: O: 2 0.200 n 0.310 2 0.387 2 0.258 0.355 n 0.110 mol O in sample OO bg += + + ⇒= C: n 0.387 0.310 0.120 mol C in sample C == H: n 2 0.355 0.310 0.220 mol H in sample
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