Elementary Principles 164 - 5.79 H 2 : Tc = (33.3 + 8) K =...

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5- 52 5.79 H T K = 41.3 K 1- butene T K P atm = 20.8 atm P atm 2c c cc :( . ) : . (. ) . =+ = = 333 8 419 6 12 8 8 39 7 T K) + 0.85(419.6 K) = 362.8 K T P atm) + 0.85(39.7 atm) = 36.9 atm P z=0.86 cr c r Fig. 5.4-2 '. ( . ( . == U V W 015 413 089 015 208 027 ± ± .. ./ m i n V= znRT P kmol h ma t m kmol K K 10 atm h 60 min m 3 3 = = 086 35 0 08206 323 1 133 ± ± m i n . V m min =u m min Am =u d 4 d= 4V u m m/min cm m cm 3 2 2 3 F H G I K J F H G I K J ×⇒ = F H G I K J = di bg π ππ 4133 150 100 10 6 5.80 4c c 24 c c 26 c c CH : T 190.7 K P 45.8 atm C H : T 283.1 K P 50.5 atm T 305.4 K P 48.2 atm T K) + 0.60(283.1 K) + 0.25(305.4 K) = 274.8 K====> T P atm) + 0.60(50.5 atm) + 0.25(48.2 atm) = 49.2 atm=====> P z = 0.67 c T=90 C r c P=175 bar r Fig. 5.4-3 o (. ( . U V | W | ⎯→ ⎯⎯⎯ 015 1907 132 015 458 35 ± V m m s A m = 10 m s s min 4 m m min 3 2 3 s F H G I K J F H G I K J F H G I K J F H G I K J = 60 0 02 0188 2 ± ± m i n . n= PV zRT bar 0.67 atm 1.013 bar kmol K .08206 m atm m K kmol / min 3 3 = = 175 1 363 163 5.81 N T K = 227.16 R P atm acetonitrile
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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