Elementary Principles 154

# Elementary Principles 154 - 5.61 (cont'd) c. W = 53,900 N V...

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5- 42 5.61 (cont’d) c. Given T, V h, find d Initial: n V RT P o o o o , == 1 bg Final: V = V dh 4 n = n (kg) 44 (kg / kmol) V RT o 2 o o ++ = + π , . . 363 00825 ± . ± ±± , / ± V= V n V 4 V RT P= W A RT V-b a VV+b d RT a 1 o 2 o piston 2 = + + =− α 00825 53 900 4 di Substitute expression for V in 1 one equation in one unknown. Solve for d ± . 5.62 a. Using ideal gas assumption: P nRT V P lb O lb - mole 32.0 lb ft psia lb - mole R R 2.5 ft psia = 2400 psig ga t m m2 m 3 o o 3 = 353 11 0 7 35 0 9 7 14 7 . .. . b. SRK Equation of state: P = RT a ± did i 33 m ideal m 32.0 lb /lb-mole 2.5 ft ft ˆ 2 . 2 7 35.3 lb lb-mole (Use as a first estimate when solving the SRK equation) = For O : T R, P psi, = 0.021 2c o c 277 9 730 4 ω a= ft psi lb - mole , b ft lb - mole
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## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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