Elementary Principles 152 - 5.58 C 3 H 8 TC = 369.9 K PC =...

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5- 40 5.58 C H T K P atm 4.26 10 Pa 38 C C 6 :. . . ==× = 369 9 42 0 0152 di ω Specific Volume 5.0 m 44.09 kg 1 kmol 75 kg 1 kmol 10 mol mm o l 3 3 3 293 10 3 . Calculate constants a 0.42747 8.314 m Pa mol K K Pa mP am o l b 0.08664 8.314 m Pa mol K K Pa o l m 3 62 3 3 = ⋅⋅ × =⋅ = × =+ = = bg e j 2 2 6 6 5 2 2 369 9 426 10 0949 369 9 625 10 0 48508 155171 0152 015613 0152 0 717 1 0 717 1 298 2 369 9 115 . . . . . . .. . . . . α SRK Equation: P o lK K o l .949 m Pa mol o l o l P Pa 7.30 atm 3 3 33 = ×−× ×× + × ⇒= × −− 8 314 298 2 2 93 10 6 25 10 115 0 2 9 31 0 2 9 0 6 2 51 0 740 10 35 3 6 . . . Ideal: P RT V o K o l Pa 8 atm 3 3 == × ± . 8 314 298 2 846 10 3 6 Percent Error: (. . ) . . 835 730 7 100% 14 4% ×= atm 30 atm 5.59 CO : T 304.2 K P 72.9 atm 2C C = 0225 Ar: T 151.2 K P 48.0 atm CC = − 0004 . P a t m = 510 ., ± V L / 50.0 mol L mol 350 0 70 Calculate constants (use R L a t m m o l K = 0 08206 .) CO : a La t m mol m , b L mol T Ar: a t m mol , b L mol T 2 2 2 2 2 = = + = = + 365 0826 0 0297
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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