Elementary Principles 148

Elementary Principles 148 - 5.54(cont'd CO 2H 2 CH 3OH(M CO...

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5- 36 5.54 (cont’d) CO + 2H CH OH(M) CO H CH OH + H O 23 22 3 2 +⇔ 3 a. Let kmol / h) extent of rxn 1, kmol / h) extent of rxn 2 12 ξ (( = = CO: n = 30- H : n = 63- 2 CO : n = 5- M: n = HO : n = N : n = 2 n 100-2 K Py Py Py K 11 1 2 41 25 2N tot 1 p M CO H p MH O CO H 2 2 2 ± ± ± ± ± ± ± , ξξ + =− U V | | | W | | | ⇒= ⋅⋅ = 3 2 2 2 2 2 1 2 2 3 di bg d i KP = n n n n n n (1) p 2 4 tot 1 tot 2 tot 1 b g b g 1 2 21 2 2 2 2 100 2 2 30 63 2 3 84 65 F H G I K J = +− −− = ± ± ± ± ± ± . ξ ξ = n n n n n n n n (2) p 2 4 tot 5 tot 3 tot 2 tot 1 b g b g 2 3 1 2 2 2 2 100 2 2 56 3 2 3 1259 F H G I K J F H G I K J F H G I K J F H G I K J = = ± ± ± ± ± ± ± ± . ξξ ξ Solve (1) and (2) for = 25.27 kmol / h = 0.0157 kmol / h 2 , 2 ± ... ± .( . ) ( .) ± .. ± ± . . n kmol CO / h 9.98% CO n H / h 26.2% H n .98 kmol CO / h 10.5% CO n M / h 53.4% M n .0157 kmol H O / h 0.03% H O n kmol / h 1 2 32 2 4 52 2 total = = = =+ = == = 30 0 2527 4 73 630 2 2527 3 0 0157 12.4 kmol 50 00157 4 0 0157 25.3 kmol 0 0157 0 49 4
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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