Elementary Principles 140 - 5.47 (cont'd) Air feed to...

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5- 28 5.47 (cont’d) Air feed to furnace: n n (kmol H S fed) (min) kmol O kmol H S kmol air 0.21 kmol O n kmol air / min air 02 2 22 0 ± . ± . . ± = = 0 0667 15 1 1 04764 Overall N balance: n n (kmol air) (min) kmol N min nk m o l N 23 ± . ± . . ± (/ m i n ) == 079 0 3764 Overall S balance: n 0.200n (kmol H S) (min) kmol S 1 kmol H S n (kmo l S 6 2 ± ± . ± /min) 1 0200 0 Overall CO balance n n (kmol CO min) 25 0 2 : ± . ± / = 0800 Overall H balance: (min) kmol H 1 kmol H S km o l HO min kmol H 1 kmol H O n = 0.200n (kmol H O / min) 2 42 2 402 ±± = .... ± n n + + = 0.377 kmol / min n = 0.24 kmol / min exit 0 =+ 0376 0200 0200 0800 0 bg ± . n = 0.4764(0.24 kmol air / min) kmol air / min air = 0114 5.48 Basis: 100 kg ore fed 82.0 kg FeS s), 18.0 kg I. 2 ( n fed = 82.0 kg FeS kmol /120.0 kg kmol FeS FeS 2 2 2 b g 1 0 6833 = . l SO) l l O) l N) 33 52 m (kg FeS FeO kg I 62 72 3 ) ) 18 24 11 2 15 2 FeS
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