Elementary Principles 137 - 5.45 Basis: R864.7 g C b1 mol...

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5- 25 5.45 Basis: 1 kg Oil 864.7 g C 1 mol 12.01 g mol C 116.5 g H 1 mol 1.01 g mol H 13.5 g S 1 mol 32.06 g mol S 5.3 g I = = = R S | | T | | bg 72 0 1153 0 4211 . . . 72 0 . mo l C 115.3 mol H 0.4211 mol S 5.3 g I 53 . ) ) ) ) g I n (mo l CO (m o l ) l HO ) o l SO l O o l N 12 2 32 42 52 62 C O C+ 1 2 OC O S O 2H 1 2 OH O 22 2 + +→ n (mol), 0.21 O , 0.79 N excess air 175 C, 180 mm Hg (gauge) a2 2 15% D a. Theoretical O 2 : 72.0 mol C 1 mol O 115.3 mol H 0.25 mol O 1 mol C 1 mol H 0.4211 mol S 1 mol O 2 101.2 mol O 2 1 mol S + += () 1.15 101.2 mol O 1 mol Air 2 Air Fed: 554 mol Air n a 0.21 mol O 2 == 3 3 3 554 mol Air 22.4 liter STP 1 m 448K 760 mm Hg 16.5 m air kg oil 1 kg oil mol 10 liter 273K 940 mm Hg = b. S balance: n 0.4211 mol SO = H balance: 115.3= 2n n 57.6 mol H O 33 2 = C balance: 0.95 72.0 = n
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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