Elementary Principles 135 - 5.42 Basis: 2 liters fed / min...

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5- 23 5.42 Basis: 2 liters fed / min Cl ads.= 2.0 L soln min g L g NaOH g soln mol 40.0 g NaOH ads. mol NaOH mol Cl 2 mol NaOH mol min 2 60 1130 012 1 0 23 1 0013 .. . = 2 L / min @ 23 C, 510 mm H O 2 D n (mo l a i r/mo l ) 2 ± / n (mol / min) y (mol Cl mol) (1- y)(mol air / mol) 1 2 ./ mol Cl min 2 Assume P 10.33 m H O P 10.33 510 m H O 10 m H O atm 2 abs in 22 =⇒ = + = bg b g 08 4 ± . n L 273K 10.84 m H O 1 mol min 296K 10.33 m H O 22.4 L STP mol min 1 2 2 == 2 00864 bg Cl balance: 0.0864y y mol Cl mol , specification is wrong 2 = 0 013 0150 5.43 a. Hygrometer Calibration ln y bR ln a y ae bR =+ = di b ln y y RR 12 21 = = = ln . . 02 10 90 5 0 08942 4 ln a ln y bR ln 10 0.08942 5 a 6.395 10 y 6.395 10 e 11 4 5 5 0.08942R =− = = × = × −− b. ± n 125 L 273K 105 kPa 1 mol min 298K 101 kPa 22.4 L STP 5.315 mol min wet gas 1 ± n 355 L 273K 115 kPa 1 mol min 348K 101 kPa
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