Elementary Principles 133

# Elementary Principles 133 - 5.39 Convert fuel composition...

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5- 21 5.39 Convert fuel composition to molar basis Basis: 100 g g CH 1 mol 16.04 g mol CH g C H 1 mol 30.07 g mol C H mol % CH 2.8 mol % C H 44 26 4 = = U V W 95 592 50 1 7 97 2 bg . . . 500 m h 3 n (mo l/h ) 0.972 CH 1 4 / ± ± ± n (kmol CO / h) n (kmol H O / h) 22 32 ± V ( S CMH ) 25% excess air air ± ± . . . n PV RT bar 500 m kmol K 313K h m bar kmol h 1 11 1 3 3 == = 0 08314 211 CH 2O CO H O C H O CO H O 6 2 42 2 2 2 2 7 2 23 +→ + + + Theoretical O = 21.1 kmol h kmol CH 2 kmol O kmol 1 kmol CH kmol C H 3.5 kmol O kmol 1 kmol C H kmol O h 2 4 2 2 0972 0028 431 . . . L N M + O Q P = Air Feed: kmol O 1 kmol Air m STP h 0.21 kmol O 1 kmol SCMH 2 3 2 125 431 224 5700 .. . b g = 5.40 Basis: 1 m gas fed @ 205 C, 1.1 bars Ac acetone 3 °= 1 m @205 C, 1.1 bar 3 D n (kmol), 10 C, 40 bar 3 D (kmo l ) y (kmol Ac / kmol) (1- y )(kmol air / kmol) p b a r 1 1 1 AC = 0100 . n (kmol Ac(l)) 2 a. n m 273K bars 1 kmol 478K bars 22.4 m STP
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## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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