Elementary Principles 116 - 5.9 P = 1 atm + 10 cm H 2 O 1m...

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5- 4 5.9 P=1 atm+ 10 cm H O m 10 cm atm 10.333 m H O atm 2 2 2 11 101 = . T = 25 C = 298.2 K , V = 2.0 m 5 min m min = 400 L min 3 3 D ± . = 040 ±± m=n mol/min MW g/mol bg b g a. ± ± . m= PV RT MW = 1.01 atm 0.08206 298.2 K gm in Latm mol K L min g mol ⋅= 400 28 02 458 b. ± . 400 K 298.2 K 22.4 L STP g L g 273 1 2802 458 = 5.10 Assume ideal gas behavior: u m s Vm s Am nRT P D4 u u nR nR T T P P D D 3 2 2 2 1 2 1 1 2 1 2 2 2 F H G I K J = = = ⋅⋅⋅ ± ± ± ± di π ( ) ( ) () ( ) 2 2 21 1 21 2 2 12 2 60.0 m 333.2K 1.80 1.013 bar 7.50 cm TPD u u 165 m sec sec 300.2K 1.53 1.013 bar 5.00 cm + == = + 5.11 Assume ideal gas behavior: n PV RT atm 5 L 300 K + = 100 100 0 08206 0 406 .. . . MW g 0.406 mol g mol Oxygen 130 32 0 5.12 Assume ideal gas behavior: Say m t = mass of tank, n g = of gas in tank N : 37.289 g m n g mol CO : 37.440 g m n mol n m o l m g 2t g g g t =+ U V | W | = = 28 02 44.1 g 0 009391 37 0256
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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