Elementary Principles 114

# Elementary Principles 114 - 5.4 a. P1 = P0 + sl gh1 P2 = P0...

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5- 2 5.4 a. PP g h g h h=h h P=P P g h m 1 N 1 Pa gh 10 s l 1 20s l 2 12 s l kg m m s kg m s N m sl 32 2 2 =+ U V | W | ⇒− = F H G I K J F H G I K J = ρ ρρ Δ ej bg 1 1 b. 1 1 c c c l x x check units! 1 kg slurry / L slurry kg crystals / kg slurry kg crystals / L crystals kg liquid / kg slurry kg liquid / L liquid L slurry kg slurry L crystals kg slurry L liquid kg slurry L slurry kg slurry = c. i.) 3 P kg / m == = Δ 2775 9 8066 0 200 1415 .. b g ii.) 11 1 1 1 c c c l c cl s ll x 1-x x F H G I K J =− F H G I K J x kg / m kg / m kg / m kg / m kg crystals / kg slurry c 3 3 33 = F H G G I K J J F H G G I K J J = 1 1415 1 12 1000 1 2 3 1000 1 12 1000 0316 . . di iii.) V m kg 1415 kg / m L m L = 175 1000 1238 . iv.) m x m kg crystals / kg slurry kg slurry kg crystals cc s l = 0 316 175 553 b g v.) m kg CuSO H O kmol 249 kg kmol CuSO kmol CuSO H O kg kmol kg CuSO CuSO 42 4 4 4 = = 5 1 1 15 159 6 1 354 . vi.) m x m kg liquid / kg slurry kg slurry kg liquid solution lc s l = = 1 0 684 175 120 bgb g b g vii.) V m k g 1.2 kg / m L m L l l l 3 3 = 120 1000
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## This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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