Elementary Principles 113 - CHAPTER FIVE 5.1 Assume volume...

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5- 1 CHAPTER FIVE 5.1 Assume volume additivity Av. density (Eq. 5.1-1): 10 4 0 0 0 0600 0 0 719 ρ =+⇒ = .. . .703 kg L .730 kg L kg L A O A D a. mm t m m = kg kg min m mass flow rate of liquid mass of tank at time 0 mass of empty tank A A =+ == t ±± min . ± 250 150 10 3 14 28 bg ⇒⇒ = = ± ± ( ± . V(L / min) = m(kg / min) kg / L) V kg 1 L min 0.719 kg Lm in 14 28 19.9 b. ( t ) - m t k g 0 150 14 28 3 107 = ± . 5.2 void volume of bed: 100 2335 184 505 33 3 cm cm cm −− = porosity: 184 0 274 cm void cm total cm void cm total = bulk density: 600 g 184 326 3 cm g cm 3 = . absolute density: 600 g 184 505 4 3 −= . cm .49 g cm 3 5.3 CH 66 () l ± ± m ( k g /m i n ) V = 20.0 L / min B B ± ± m (kg / min) V (L / min)
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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