Elementary Principles 112 - 4.80 a. Basis: 1 mol CpHqOr 1...

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4- 71 4.80 a. Basis : 1 mol C p H q O r C + 02 --> CO2 2H + 1/2 O2 -->H2O S + O2 --> SO2 1 mol C p H q O r no (mol S) X s (kg s/ kg fuel) P (% excess air) n 1 (mol O 2 ) 3.76 n 1 (mol N 2 ) n 2 (mol CO 2 ) n 3 (mol SO 2 ) n 4 (mol O 2 ) 3.76 n 1 (mol N 2 ) n 5 (mol H 2 O (v)) Hydrocarbon mass: p (mol C) ( 12 g / mol) = 12 p (g C) q (mol H) (1 g / mol) = q (g H) (12 p + q + 16 r) g fuel r (mol O) (16 g / mol) = 16 r (g O) S in feed: n o = S) (mol ) X - (1 07 . 32 r) 16 q p (12 X S g 32.07 S mol 1 fuel) (g ) X - (1 S) (g X fuel g 16r) q p (12 s s s s + + = + + (1) Theoretical O 2 : O mol 2 O mol 1 O) mol r ( H mol 2 O mol 0.5 H) (mol q C mol 1 O mol 1 C) (mol p 2 2 2 + O mol r) /2 1 q 1/4 (p 2 + = % excess n 1 = (1 + P /100) ( p +1/4 q – ½ r ) mol O 2 fed (2) C balance: n 2 = p ( 3 ) H balance: n 5 = q / 2 ( 4 ) S balance: n 3 = n 0 (5) O balance: r + 2 n 1 = 2 n 2 + 2 n 3 + 2 n 4 + n 5 n 4 = ½ ( r +2 n 1 -2 n 2 -2 n 3 - n 5 ) (6) Given : p = 0.71, q = 1.1,
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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