Elementary Principles 108 - 4.75 (cont'd) H: 0.17 5000 kg H...

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4- 67 4.75 (cont’d) H : 0.17 5000 kg H 1 kmol H 1 kmol H O 1 kmol O h kg H 2 kmol H 2 kmol H O 22 2 bg 101 . = 210 4 . km o l O h 2 S : 0.02 5000 kg S 1 kmol S 1 kmol O h1 k m o l S 2 32.06 kg S = 3.1 kmol O 2 /h Total = (312.2+210.4 + 3.1) kmol O 2 /h = 525.7 kmol O h 2 O f e d 2 = 0 21 3000 630 . = kmol O h 2 Excess air : 630 5257 100% 19 8% ×= . . . excess air b. Balances: C : 094 075 12 01 .. . ±± b g 5000 kg C react 1 kmol C h k g C 0.1 33 =+ nn ⇒= ± . n 32 kmol CO h 2668 , 01 267 . ± . n 3 kmol CO h = H : 017 . . b g 5000 kg H 1 kmol H 1 kmol H O h kg H 2 kmol H 2 5 = n = n 52 kmol H O h 4208 . S : (from part a) 3.1 kmol O for SO 1 kmol SO k m o l O 2 2 4 1 = ± n = ± . n 42 kmol SO h 31 N 2 : 0 79 3000 . ± b g kmol N h n = = ± n kmol N h 2370 O : 0 21 3000 2
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This note was uploaded on 02/27/2012 for the course CHEMICAL E 312 taught by Professor Cheung during the Fall '11 term at The University of Akron.

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